1. A gas occupies 12.3 Liters at a pressure of 40.0 mmHg. What is the volume when the pressure is increased to 60.0 mmHg?
Let's break this down in to smaller steps. First, we need to identify all of our values. The easiest way to do this is to make a list of the what the formula consists of. The formula for Boyle's Law is
P1 x V1 = P2 x V2. So, our list will look like this:
P1 = __
V1 = __
P2 = __
V2 = __
Now, let's fill in the blanks.
P1 = 40.0 mmHG
V1 = 12.3 Liters
P2 = 60.0 mmHg
V2 = ?
Now we know we need to solve for V2, or the new/final volume. Let's plug our values into the formula:
(40.0 mmHg)(12.3 L) = (60.0 mmHg)(V2)
(492 mmHg/L) = (60.0mmHg)(V2)
Divide both sides by 60.0 mmHg and carry out the units
8.20 L = V2
The answer is 8.20 Liters due to significant figures as well as the fact that our original volume was in liters.
Charles' Law
600.0 mL of air is at 20.0 degrees Celsius. What is the volume at 60.0 degrees Celsius?
Like Boyle's Law, let's break this down into smaller steps. First, we need to identify all of our values. The easiest way to do this is to make a list of what the formula consists of. The formula for Charles' Law is V1/T1 = V2/T2. Our list will look like this:
V1 = __
T1 = __
V2 = __
T2 = __
Now, let's fill in the blanks with what we know.
V1 = 600.0 mL
T1 = 20.0 degrees Celsius (When converted to Kelvin, T1 = 293K)
V2 = ?
T2 = 60.0 degrees Celsius (When converted to Kelvin, T2 = 333K)
Now we know we need to solve for V2, or the new/final volume. Let's plug in our values into the formula.
(600.0 mL)/ 293K = V2/ 333K
2.04778 mL/K = V2/333K
Multiply each side by 333K and carry out units
682 mL = V2
The answer is 682 mL due to rounding/significant figures and the fact that our original volume was in mL.
Charles' Law
600.0 mL of air is at 20.0 degrees Celsius. What is the volume at 60.0 degrees Celsius?
Like Boyle's Law, let's break this down into smaller steps. First, we need to identify all of our values. The easiest way to do this is to make a list of what the formula consists of. The formula for Charles' Law is V1/T1 = V2/T2. Our list will look like this:
V1 = __
T1 = __
V2 = __
T2 = __
Now, let's fill in the blanks with what we know.
V1 = 600.0 mL
T1 = 20.0 degrees Celsius (When converted to Kelvin, T1 = 293K)
V2 = ?
T2 = 60.0 degrees Celsius (When converted to Kelvin, T2 = 333K)
Now we know we need to solve for V2, or the new/final volume. Let's plug in our values into the formula.
(600.0 mL)/ 293K = V2/ 333K
2.04778 mL/K = V2/333K
Multiply each side by 333K and carry out units
682 mL = V2
The answer is 682 mL due to rounding/significant figures and the fact that our original volume was in mL.
